TomSym Production of Alloys: Difference between revisions

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(Created page with "{{Part Of Manual|title=the TomSym Manual|link=TomSym Manual}} ==Problem description== The company Steel has received an order for 500 tonnes of steel to be used in s...")
 
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Characteristics of steel ordered
Characteristics of steel ordered


<pre>
+---------------+-------+-------+
+---------------+-------+-------+
|Chemical      |Minimum|Maximum|
|Chemical      |Minimum|Maximum|
Line 15: Line 16:
|Manganese (Mn) |  1.2  | 1.65  |
|Manganese (Mn) |  1.2  | 1.65  |
+---------------+-------+-------+
+---------------+-------+-------+
</pre>


The company has seven different raw materials in stock that may be used for the production of this steel. The table below lists the grades, available amounts and prices for all raw materials.
The company has seven different raw materials in stock that may be used for the production of this steel. The table below lists the grades, available amounts and prices for all raw materials.
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Raw material grades, availabilities, and prices
Raw material grades, availabilities, and prices


<pre>
+----------------+---+----+----+------------+----+
+----------------+---+----+----+------------+----+
|Raw material    |C %|Cu %|Mn %|Availability|Cost|
|Raw material    |C %|Cu %|Mn %|Availability|Cost|
Line 31: Line 34:
|Aluminum alloy 2| 0 | 0.6|0  |    250    |165 |
|Aluminum alloy 2| 0 | 0.6|0  |    250    |165 |
+----------------+---+----+----+------------+----+
+----------------+---+----+----+------------+----+
</pre>


The objective is to determine the composition of the steel that minimizes the production cost.
The objective is to determine the composition of the steel that minimizes the production cost.
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==Variables==
==Variables==


<pre>
compsize            Amount of steel to produce
compsize            Amount of steel to produce
mincomp              Minimal contents of each component.
mincomp              Minimal contents of each component.
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rawavail            Amount available of raw material.
rawavail            Amount available of raw material.
rawcost              Cost of raw material.
rawcost              Cost of raw material.
</pre>


==Reference==
==Reference==

Revision as of 17:25, 2 November 2011

Notice.png

This page is part of the TomSym Manual. See TomSym Manual.

Problem description

The company Steel has received an order for 500 tonnes of steel to be used in shipbuilding. This steel must have the following characteristics (‘grades’).

Characteristics of steel ordered

+---------------+-------+-------+
|Chemical       |Minimum|Maximum|
|Element        |Grade  |Grade  |
+---------------+-------+-------+
|Carbon (C)     |  2.0  | 3.0   |
|Copper (Cu)    |  0.4  | 0.6   |
|Manganese (Mn) |  1.2  | 1.65  |
+---------------+-------+-------+

The company has seven different raw materials in stock that may be used for the production of this steel. The table below lists the grades, available amounts and prices for all raw materials.

Raw material grades, availabilities, and prices

+----------------+---+----+----+------------+----+
|Raw material    |C %|Cu %|Mn %|Availability|Cost|
+----------------+---+----+----+------------+----+
|Iron alloy 1    |2.5| 0  |1.3 |     400    |200 |
|Iron alloy 2    | 3 | 0  |0.8 |     300    |250 |
|Iron alloy 3    | 0 | 0.3|0   |     600    |150 |
|Copper alloy 1  | 0 | 90 |0   |     500    |220 |
|Copper alloy 2  | 0 | 96 |4   |     200    |240 |
|Aluminum alloy 1| 0 | 0.4|1.2 |     300    |200 |
|Aluminum alloy 2| 0 | 0.6|0   |     250    |165 |
+----------------+---+----+----+------------+----+

The objective is to determine the composition of the steel that minimizes the production cost.

Variables

compsize             Amount of steel to produce
mincomp              Minimal contents of each component.
maxcomp              Maximal contents of each component.
rawcompmat           Contents of raw material.
rawavail             Amount available of raw material.
rawcost              Cost of raw material.

Reference

Applications of optimization... Gueret, Prins, Seveaux

% Marcus Edvall, Tomlab Optimization Inc, E-mail: tomlab@tomopt.com
% Copyright (c) 2005-2009 by Tomlab Optimization Inc., $Release: 7.2.0$
% Written Oct 7, 2005.   Last modified Apr 8, 2009.

Problem setup

compsize   = 500;
mincomp    = [2;.4;1.2];
maxcomp    = [3;.6;1.65];
rawcompmat = [[2.5;  3;  0;  0;  0;  0;  0],...
    [  0;  0; .3; 90; 96; .4; .6],...
    [1.3; .8;  0;  0;  4;1.2;  0]];
rawavail   = [ 400;300;600;500;200;300;250];
rawcost    = [ 200;250;150;220;240;200;165];

comp = tom('comp',7,1);
objective = rawcost'*comp;
prodcons = {compsize == sum(comp)};
compminmax = {mincomp*compsize <= rawcompmat'*comp <= maxcomp*compsize};
availcons = {0 <= comp <= rawavail};
constraints = {prodcons, compminmax, availcons};
options = struct;
options.solver = 'cplex';
options.name = 'Production of Alloys';
sol = ezsolve(objective,constraints,[],options);

PriLev = 1;
if PriLev > 0
    names = [ 'Iron 1' ; 'Iron 2' ; 'Iron 3' ; 'Copp 1' ; ...
        'Copp 2' ; 'Alum 1' ; 'Alum 2'];
    disp('the optimal steel contains:');
    for i = 1:length(sol.comp),
        if sol.comp(i) > 0,
            disp(['   ' num2str(sol.comp(i)) ' tonnes of ' names(i,:) ])
        end
    end
end

% MODIFICATION LOG
%
% 051007 med   Created.
% 060110 per   Added documentation.
% 060125 per   Moved disp to end
% 090308 med   Converted to tomSym
Problem type appears to be: lp
Time for symbolic processing: 0.014988 seconds
Starting numeric solver
===== * * * =================================================================== * * *
TOMLAB - TOMLAB Development license  999007. Valid to 2011-12-31
=====================================================================================
Problem: ---  1: Production of Alloys           f_k   98121.635791681227000000
                                       sum(|constr|)      0.000000000000000947
                              f(x_k) + sum(|constr|)  98121.635791681227000000
                                              f(x_0)      0.000000000000000000

Solver: CPLEX.  EXIT=0.  INFORM=1.
CPLEX Dual Simplex LP solver
Optimal solution found

FuncEv    5 Iter    5 
Elapsed time: 0.002000 sec. 
the optimal steel contains:
   400 tonnes of Iron 1
   39.7763 tonnes of Iron 3
   2.7613 tonnes of Copp 2
   57.4624 tonnes of Alum 1